0.5x^2+88x+24=0

Solution for 0.5x^2+88x+24=0 equation:

0.5x^2+88x+24=0

a = 0.5; b = 88; c = +24;
Δ = b2-4ac
Δ = 882-4·0.5·24
Δ = 7696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7696}=\sqrt{16*481}=\sqrt{16}*\sqrt{481}=4\sqrt{481}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-4\sqrt{481}}{2*0.5}=\frac{-88-4\sqrt{481}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+4\sqrt{481}}{2*0.5}=\frac{-88+4\sqrt{481}}{1}
$